# How do you solve by completing the square for y=3x^2+24x+8?

$y = 3 \left({x}^{2} + 8 x + 16\right) - 48 + 8$
$y = 3 {\left(x + 4\right)}^{2} - 40$
${\left(x + 4\right)}^{2} = \frac{40}{3} \to \left(x + 4\right) = \pm \frac{2 \sqrt{10}}{\sqrt{3}}$=$\pm \frac{2 \sqrt{30}}{3}$
$x = - \frac{24}{6} \pm \frac{2 \sqrt{30}}{18} = - 6 \pm \frac{\sqrt{30}}{9}$