How do you solve by elimination #x + y = 2# and #2x + y = -1#? Algebra Systems of Equations and Inequalities Linear Systems with Addition or Subtraction 1 Answer Dean R. Apr 27, 2018 #x=-3, y=5# Explanation: Subtracting equations, #x - 2x = 2 - -1# #-x = 3# #x = -3# #y = 2 - x= 2 - -3 = 5# Check: #-3 + 5 = 2 quad sqrt# # 2(-3) + 5 = -1 quad sqrt# Answer link Related questions What if the elimination method results in 0=0? How do you use the addition and subtraction method to solve a linear system? Can any system be solved using the addition and subtraction method? When is the addition and subtraction method easier to use? How do you solve #-x-6y=-18# and #x-6y=-6# using the addition and subtraction method? How do you solve #5x-3y=-14# and #x-3y=2# using elimination? Do you need to add or subtract the equations #5x+7y=-31# and #5x-9y=17# to solve the system? How do you solve the system of equations #3y-4x=-33# and #5x-3y=40.5#? What is the solution to the system #x+y=2# and #x-y=6#? What is the common point of #x+2y=6# and #x+y=2#? See all questions in Linear Systems with Addition or Subtraction Impact of this question 2515 views around the world You can reuse this answer Creative Commons License