# How do you solve by factoring 6x^2 - x - 3= 0?

Mar 30, 2016

To factor a trinomial of the form $y = a {x}^{2} + b x + c , a \ne 1$, you must find two numbers so that they multiply to $a \times c$ and they add to b.
Going through the factors of 18: (-1, 18); (18, -1); (6,-3); (-3, 6); (-9,2); (-2, 9), we see that none of those pairs add to -1.