# How do you solve c^2+10c+9=0?

$c = - 1$ or $c = - 9$
${c}^{2} + 10 c + 9 = 0$
$\left(c + 1\right) \left(c + 9\right) = 0$
$c + 1 = 0$ or $c + 9 = 0$
$c = - 1$ or $c = - 9$