# How do you solve compound inequalities 4x<16 or 12x>144?

$\left\{x | x < 4 \mathmr{and} x > 12\right\}$
we'll look at $4 x < 16$: let's devide it by 4 and we obtain: $x < 4$
let's look at the other one: $12 x > 144$. we divide it by 12 and obtain $x > 12$. so we have that $x < 4$ , $x > 12$, which means: that x must be less than 4, or x must bigger than 12 i.e: $\left\{x | x < 4 \mathmr{and} x > 12\right\}$