Question

How do you solve `cos(3x)=sqrt3/2` and find all solutions in the interval `0<=x<360`?

Answer 1

`10^@; 110^@`

Explanation:

`cos 3x= sqrt3/2`
Trig table and unit circle give 2 solutions:
`3x = +- 30^@`

a. `3x = 30^@` --> `x = 10^@`
b. `3x = - 30^@` , or `3x = 330^@` (co-terminal) -->
`x = 110^@`