Question

How do you solve `cosx/2=sqrt2/4`?

Answer 1

`x=2npi+-pi/4`, where `n` is an integer.

Explanation:

As `cosx/2=sqrt2/4`

`cosx=sqrt2/4xx2=sqrt2/2=1/sqrt2`

Now as `cos(+-pi/4)=1/sqrt2`

`x=2npi+-pi/4`, where `n` is an integer.