Question

How do you solve `cosx=sqrt3/2`?

Answer 1

`x=2npi+-pi/6`, where `n` is an integer.

Explanation:

As `cosx=sqrt3/2`, `x` is positive and hence can be in

either first quadrant i.e. `x=pi/6` or in fourth quadrant i.e. `x=-pi/6`

Further adding `+-2pi` to `x` too does not change value of `cosx`

Hence `x=2npi+-pi/6`, where `n` is an integer.