Question

How do you solve `cosx(tanx-sqrt3)=0` and find all solutions in the interval `0<=x<360`?

Answer 1

`pi/3; pi/2; (4pi)/3, (3pi)/2`

Explanation:

`f(x) = cos x(tan x - sqrt3) = 0`
Either factor should be zero.
a. `cos x = 0` --> Unit circle gives -->
`x = pi/2` and `x = (3pi)/2`
b. `tan x = sqrt3` --> trig table and unit circle give -->
`x = pi/3` and `x = pi/3 + pi = (4pi)/3`