How do you solve #cotxsecx+cotx=0# and find all general solutions?

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Answer 1 · 2016-10-03T03:22:52

Factor:

#cosx/sinx(1/cosx) + cosx/sinx= 0#

#1/sinx + cosx/sinx = 0#

#(1 + cosx)/(sinx) = 0#

#1 + cosx = 0#

#cosx= -1#

#x = pi + pin#, n an integer.

However, this solution renders the equation undefined, so there is no real solution.

Hopefully this helps!