How do you solve $e^{3 k} = 5$ $e^(3k) = 5$ ?

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Answer 1 · 2015-12-06T20:14:06

$k = \frac{ln 5}{3}$ $k=ln5/3$

Take the natural logarithm on both sides and then use laws of logs to yield

${ln e}^{3 k} = ln 5$ $lne^(3k)=ln5$

$therefore3klne=ln5$

$thereforek=ln5/3$

How do you solve e^(3k) = 5e3k=5e^(3k) = 5?