How do you solve for a in # sa=2ab+2ac+2bc #?
1 Answer
Feb 26, 2016
Explanation:
First, get all the terms with
Here, I'll subtract
#sa-2ab-2ac=2bc#
Factor
#a(s-2b-2c)=2bc#
Divide both sides by
#a=(2bc)/(s-2b-2c)#
This is as simplified as possible. Resist the urge to try to break apart the denominator--that's not allowed.