# How do you solve for a in # sa=2ab+2ac+2bc #?

##### 1 Answer

Feb 26, 2016

#### Explanation:

First, get all the terms with

Here, I'll subtract

#sa-2ab-2ac=2bc#

Factor

#a(s-2b-2c)=2bc#

Divide both sides by

#a=(2bc)/(s-2b-2c)#

This is as simplified as possible. Resist the urge to try to break apart the denominator--that's not allowed.