# How do you solve for b in -2(3a-b)=c?

Mar 29, 2016

$b = \frac{c + 6 a}{2}$

#### Explanation:

$- 2 \left(3 a - \textcolor{b l u e}{b}\right) = c$

$\left(- 2\right) \cdot \left(3 a\right) + \left(- 2\right) \cdot \left(- b\right) = c$

$- 6 a + \textcolor{b l u e}{2 b} = c$

$\textcolor{b l u e}{2 b} = c + 6 a$

$\textcolor{b l u e}{b} = \frac{c + 6 a}{2}$