How do you solve for B in S=2B+Ph?

Jul 5, 2017

See a solution process below:

Explanation:

First, subtract $\textcolor{red}{P h}$ from each side of the equation to isolate the $B$ term while keeping the equation balanced:

$S - \textcolor{red}{P h} = 2 B + P h - \textcolor{red}{P h}$

$S - P h = 2 B + 0$

$S - P h = 2 B$

Now, divide each side of the equation by $\textcolor{red}{2}$ to solve for $B$ while keeping the equation balanced:

$\frac{S - P h}{\textcolor{red}{2}} = \frac{2 B}{\textcolor{red}{2}}$

$\frac{S - P h}{2} = \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} B}{\cancel{\textcolor{red}{2}}}$

$\frac{S - P h}{2} = B$

$B = \frac{S - P h}{2}$

Or

$B = \frac{S}{2} - \frac{P h}{2}$