# How do you solve for c in 2a+3b+c=0 ?

Jul 29, 2017

See a solution process below:

#### Explanation:

Subtract color(red)(-(2a + 3b) from each side of the equation to solve for $c$ while keeping the equation balanced:

$2 a + 3 b - \left(2 a + 3 b\right) + c = 0 - \left(2 a + 3 b\right)$

$\left(2 a + 3 b\right) - \left(2 a + 3 b\right) + c = 0 - 2 a - 3 b$

$0 + c = - 2 a - 3 b$

$c = - 2 a - 3 b$