Question

How do you solve for d in `2x-2yd= y + xd`?

Answer 1

`color(blue)(d = (2x -y) / ( x+2y)`

Explanation:

`2x - 2ycolor(blue)(d) = y +xcolor(blue)(d`

Isolating terms containing `color(blue)(d`

`2x -y = xcolor(blue)(d) + 2ycolor(blue)(d)`

`2x -y = color(blue)(d) ( x+2y)`

`color(blue)(d = (2x -y) / ( x+2y)`