How do you solve for F in #C=5/9(F-32)#?

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Answer 1 · 2016-05-09T22:01:33

#F = 9/5C+32#

Given:

#C = 5/9(F-32)#

First multiply both sides by #9/5# to get:

#9/5C = F-32#

Add #32# to both sides and transpose to get:

#F = 9/5C+32#

These are the formulas to translate between Fahrenheit and Celsius temperatures.

Fahrenheit and Celsius meet at #-40# degrees.

That is #-40^@F = -40^@C#

So alternative formulas for the conversions can be written:

#F = 9/5(C+40)-40#

#C = 5/9(F+40)-40#