Question

How do you solve for G in `AL+G/EB=R+A`?

Answer 1

See the entire solution process below:

Explanation:

First, subtract `color(red)(AL)` from each side of the equation to isolate the term containing the `G` while keeping the equation balanced:

`AL + G/EB - color(red)(AL) = R + A - color(red)(AL)`

`AL - color(red)(AL) + G/EB = R + A - AL`

`0 + G/EB = R + A - AL`

`G/EB = R + A - AL`

Now, multiply each side of the equation by `color(red)(E)/color(blue)(B)` to solve for `G` while keeping the equation balanced:

`color(red)(E)/color(blue)(B) * G/EB = color(red)(E)/color(blue)(B)(R + A - AL)`

`cancel(color(red)(E))/cancel(color(blue)(B)) * G/color(red)(cancel(color(black)(E)))color(blue)(cancel(color(black)(B))) = color(red)(E)/color(blue)(B)(R + A - AL)`

`G = color(red)(E)/color(blue)(B)(R + A - AL)`

Or

`G = (color(red)(E)(R + A - AL))/B`

Or

`G = (ER + EA - EAL)/B`

Or

`G = (ER)/B + (EA)/B - (EAL)/B`