# How do you solve for h? -4h+3+7h≥9h-21

We will first rearrange to put all $h$s on one side:
$3 \le 9 h - 7 h + 4 h - 21$
$3 \le 6 h - 21$
Now we add $21$ to both sides:
$3 + 21 \le 6 h - 21 + 21$
$24 \le 6 h$
$F \in a l l y , w e \div i \mathrm{de} \bot h s i \mathrm{de} s b y$6: 24/6le(6h)/6 4leh#