# How do you solve for h: in -3/7h = 6?

##### 1 Answer
May 2, 2016

$h = - \frac{42}{3}$

#### Explanation:

The objective is to get only one $h$ and for it to be on one side of the equals and everything else on the other side.

Multiply both sides by 7

$- \frac{3 h}{7} \times 7 = 6 \times 7$

$- 3 h \times \frac{7}{7} = 42$

But $\frac{7}{7} = 1$ and anything multiplied by 1 does not change its inherent value.

$- 3 h = 42$

Divide both sides by 3#

$- \frac{3}{3} \times h = \frac{42}{3}$

But $- \frac{3}{3} = - 1$

$- h = \frac{42}{3}$

Multiply both sides by $\left(- 1\right)$

$+ h = - \frac{42}{3}$