How do you solve for h: in #-3/7h = 6#?

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Answer 1 · 2016-05-02T11:06:23

#h=-42/3#

The objective is to get only one #h# and for it to be on one side of the equals and everything else on the other side.

Multiply both sides by 7

#-(3h)/7 xx7=6xx7#

#-3hxx7/7=42#

But #7/7=1# and anything multiplied by 1 does not change its inherent value.

#-3h=42#

Divide both sides by 3#

#-3/3xxh=42/3#

But #-3/3=-1#

#-h=42/3#

Multiply both sides by #(-1)#

#+h=-42/3#