# How do you solve for k in 3k+6t=b+5?

May 3, 2016

$k = \frac{1}{3} \left(b + 5 - 6 t\right)$

#### Explanation:

Isolate the k term on the left side and place all other terms on the right.

hence : 3k = b + 5 - 6t

Now divide both sides by 3 to obtain k.

$\Rightarrow \frac{\cancel{3} k}{\cancel{3}} = \frac{b + 5 - 6 t}{3} = \frac{1}{3} \left(b + 5 - 6 t\right)$