# How do you solve for K in F= 9/5(K-273)+32?

May 17, 2016

$K = \frac{5}{9} \left(F - 32\right) + 273$

#### Explanation:

Subtract 32 from both sides

$F - 32 = \frac{9}{5} \left(K - 273\right)$

Multiply both sides by $\frac{5}{9}$

$\frac{5}{9} \left(F - 32\right) = \left(\frac{9}{5} \times \frac{5}{9}\right) \left(K - 273\right)$

$\frac{5}{9} \left(F - 32\right) = 1 \times \left(K - 273\right)$

$K = \frac{5}{9} \left(F - 32\right) + 273$