How do you solve for m in #10m-p = -n + p m#?

1 Answer
Jul 25, 2016

#color(green)(m=(p-n)/(10-p)#

Explanation:

Given
#color(white)("XXX")10m-p=-n+p m#

We need to get all the terms involving #m# on one side and all other terms on the other side:
#color(white)("XXX")10m-p*m =p-n#

Extract the factor of #m# from the terms on the left side
#color(white)("XXX")m(10-p)=p-n#

(Assuming #p!=10#) divide both sides by #(10-p)# isolating a single #m# on the left side
#color(white)("XXX")m=(p-n)/(10-p)#