# How do you solve for n in 2n - 4m = 8?

Mar 10, 2018

See a solution process below:

#### Explanation:

First, add $\textcolor{red}{4 m}$ to each side of the equation to isolate the $n$ term while keeping the equation balanced:

$2 n - 4 m + \textcolor{red}{4 m} = 8 + \textcolor{red}{4 m}$

$2 n - 0 = 8 + 4 m$

$2 n = 8 + 4 m$

Now, divide by $\textcolor{red}{2}$ to solve for $n$ while keeping the equation balanced:

$\frac{2 n}{\textcolor{red}{2}} = \frac{8 + 4 m}{\textcolor{red}{2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} n}{\cancel{\textcolor{red}{2}}} = \frac{8}{\textcolor{red}{2}} + \frac{4 m}{\textcolor{red}{2}}$

$n = 4 + 2 m$

Mar 10, 2018

$n = 2 \left(m + 2\right)$

#### Explanation:

Add $4 m$ to both sides

$2 n = 8 + 4 m$

Divide both sides by $2$

$n = 4 + 2 m$

Take a factor of $2$ out of $4 m + 2$

$n = 2 \left(2 + m\right)$