How do you solve for p in #3p - 2q = 37#?
1 Answer
Jun 3, 2018
Explanation:
#"isolate "3p" by adding "2q" to both sides"#
#3pcancel(-2q)cancel(+2q)=37+2q#
#3p=37+2q#
#"divide both sides by 3"#
#(cancel(3) p)/cancel(3)=(37+2q)/3#
#p=(37+2q)/3=1/3(37+2q)#