# How do you solve for p in 3p - 2q = 37?

Jun 3, 2018

$p = \frac{1}{3} \left(37 + 2 q\right)$

#### Explanation:

$\text{isolate "3p" by adding "2q" to both sides}$

$3 p \cancel{- 2 q} \cancel{+ 2 q} = 37 + 2 q$

$3 p = 37 + 2 q$

$\text{divide both sides by 3}$

$\frac{\cancel{3} p}{\cancel{3}} = \frac{37 + 2 q}{3}$

$p = \frac{37 + 2 q}{3} = \frac{1}{3} \left(37 + 2 q\right)$