How do you solve for q in #s = 4p + 4q#?

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Answer 1 · 2017-01-31T06:02:45

#p=(s-4p)/4#

Given-

#s=4p+4q#

To solve for #q#

Rewrite the equation

#4p+4q=s#

Add #-4p # on both sides

#cancel(4p)+4qcancel(-4p)=s-4p#

Multiply both sides by #1/4#

#(cancel4p)/cancel4=(s-4p)*1/4#

#p=(s-4p)/4#