How do you solve for $u$ $u$ in the equation $- 9 + u = 4 u$ $-9 + u = 4u$ ?

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Answer 1 · 2018-03-12T09:59:13

$u = - 3$ $u=-3$

$- 9 + u = 4 u$ $-9+u=4u$

$\Rightarrow - 9 = 4 u - u$ $=> -9=4u-u$

$\Rightarrow - 9 = 3 u$ $=> -9=3u$

$\Rightarrow - \frac{9}{3} = u$ $=> -9/3=u$

$=> (-cancel9^3)/cancel3=u$

$=> -3=u$

How do you solve for uuu in the equation -9 + u = 4u−9+u=4u-9 + u = 4u?