# How do you solve for x: -4/5(x-3)≤-12?

Jun 17, 2018

$x = 18$

#### Explanation:

$- \frac{4}{3} \left(x - 3\right) \le - 12$

First, divide both sides by $\textcolor{b l u e}{- 4}$:
$\frac{- \frac{4}{5} \left(x - 3\right)}{\textcolor{b l u e}{- 4}} \le \frac{- 12}{\textcolor{b l u e}{- 4}}$

$\frac{1}{5} \left(x - 3\right) \le 3$

Now multiply both sides by $\textcolor{b l u e}{5}$:
$\frac{1}{5} \left(x - 3\right) \textcolor{b l u e}{\cdot 5} \le 3 \textcolor{b l u e}{\cdot 5}$

$x - 3 \le 15$

Add $\textcolor{b l u e}{3}$ to both sides:
$x - 3 \quad \textcolor{b l u e}{+ \quad 3} \le 15 \quad \textcolor{b l u e}{+ \quad 3}$

Therefore,
$x \le 18$

Hope this helps!