How do you solve for x in #1/2ax=c#?

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Answer 1 · 2016-02-13T18:58:17

#x=(2c)/a#

To isolate #x#, let's first try to deal with the #1/2#.

When undoing fractions, multiply both sides by the reciprocal of the fraction. The reciprocal of #1/2# is #2/1#, so multiply both sides by #2/1#.

#2/1xx1/2ax=cxx2/1#

Note that #2/1xx1/2=1# on the left side.

#ax=2c#

Now, to isolate #x# fully, divide both sides by #a#.

#(ax)/a=(2c)/a#

#x=(2c)/a#