# How do you solve for x in 4(x+a)=3(x+b)?

Jul 10, 2018

$x = 3 b - 4 a$

#### Explanation:

Expanding we get

$4 x + 4 a = 3 x + 3 b$

subtracting $3 x$ and $4 a$

$x = 3 b - 4 a$

Jul 10, 2018

$x = 3 b - 4 a$

#### Explanation:

$\text{distribute the brackets on both sides of the equation}$

$4 x + 4 a = 3 x + 3 b$

$\text{subtract "3x" from both sides}$

$4 x - 3 x + 4 a = 3 b$

$x + 4 a = 3 b$

$\text{subtract "4a" from both sides}$

$x = 3 b - 4 a$

Jul 10, 2018

$x = - 4 a + 3 b$

#### Explanation:

We can use the distributive property on both sides to get

$4 x + 4 a = 3 x + 3 b$

We want all of our $x$ terms on the left, so let's subtract $3 x$ from both sides to get

$x + 4 a = 3 b$

Finally, let's subtract $4 a$ from both sides to get

$x = - 4 a + 3 b$

Hope this helps!