Question

How do you solve for x in `4(x+a)=3(x+b)`?

Answer 1

`x=3b-4a`

Explanation:

Expanding we get

`4x+4a=3x+3b`

subtracting `3x` and `4a`

`x=3b-4a`

Answer 2

`x=3b-4a`

Explanation:

`"distribute the brackets on both sides of the equation"`

`4x+4a=3x+3b`

`"subtract "3x" from both sides"`

`4x-3x+4a=3b`

`x+4a=3b`

`"subtract "4a" from both sides"`

`x=3b-4a`

Answer 3

`x=-4a+3b`

Explanation:

We can use the distributive property on both sides to get

`4x+4a=3x+3b`

We want all of our `x` terms on the left, so let's subtract `3x` from both sides to get

`x+4a=3b`

Finally, let's subtract `4a` from both sides to get

`x=-4a+3b`

Hope this helps!