How do you solve for x in #4(x+a)=3(x+b)#?

3 Answers
Jul 10, 2018

Answer:

#x=3b-4a#

Explanation:

Expanding we get

#4x+4a=3x+3b#

subtracting #3x# and #4a#

#x=3b-4a#

Jul 10, 2018

Answer:

#x=3b-4a#

Explanation:

#"distribute the brackets on both sides of the equation"#

#4x+4a=3x+3b#

#"subtract "3x" from both sides"#

#4x-3x+4a=3b#

#x+4a=3b#

#"subtract "4a" from both sides"#

#x=3b-4a#

Jul 10, 2018

Answer:

#x=-4a+3b#

Explanation:

We can use the distributive property on both sides to get

#4x+4a=3x+3b#

We want all of our #x# terms on the left, so let's subtract #3x# from both sides to get

#x+4a=3b#

Finally, let's subtract #4a# from both sides to get

#x=-4a+3b#

Hope this helps!