# How do you solve for x in #8ax-7a^2=19a^2-5ax#?

##### 2 Answers

#### Explanation:

Collecting like terms;

**Note:** When crossing over a Negative value or unknown in a algebraic expression, the sign changes the the Positive value, also when crossing over a Positive value or uknown the sign changes to a Negative value, (Vice-Versa)

Simplifying;

Dividing both sides by the coefficient of

#### Explanation:

#"collect terms in x together on the left side and other"#

#"terms on the right side"#

#"add "5ax" to both sides"#

#8ax+5ax-7a^2=19a^2cancel(-5x)cancel(+5x)#

#13ax-7a^2=19a^2#

#"add "7a^2" to both sides"#

#13ax=19a^2+7a^2#

#13ax=26a^2#

#"divide both sides by "13a#

#(cancel(13a) x)/cancel(13a)=(26a^2)/(13a)rArrx=2a#