# How do you solve for x in A= 3/4 (p) (a+x)?

Mar 18, 2016

$x = \frac{4 A}{3 p} - a$

#### Explanation:

$A = \textcolor{b l u e}{\left(\frac{3}{4}\right)} \cdot \left(p\right) \left(a + x\right)$

$A \cdot \textcolor{b l u e}{\left(\frac{4}{3}\right)} = \textcolor{g r e e n}{\left(p\right)} \left(a + x\right)$

$\frac{4}{3} A = \textcolor{g r e e n}{\left(p\right)} \cdot \left(a\right) + \textcolor{g r e e n}{\left(p\right)} \cdot \left(x\right)$

$\frac{4 A}{3} = p a + p x$

$\frac{4 A}{3} = \textcolor{p u r p \le}{p} \cdot \left(a + x\right)$

$\frac{4 A}{3 \cdot \textcolor{p u r p \le}{p}} = a + x$

$\frac{4 A}{3 p} = a + x$

$\frac{4 A}{3 p} - a = x$