Question

How do you solve for x in `ax+b=0`?

Answer 1

`x=-b/a`

Explanation:

Given:`" "color(brown)(ax+b=0)`

Subtract `color(blue)(b)` from both sides

`" "color(brown)(ax+bcolor(blue)(-b)=0color(blue)(-b))`

`" "ax+0=-b`

`" "color(brown)(ax=-b)`

Divide both sides by `color(blue)(a)` giving

`" "color(brown)(a/(color(blue)(a))xxx=-b/(color(blue)(a))`

But `a/a=1`

`" "color(green)(x=-b/a)`