How do you solve for x in $a x - c = b$ $ax-c=b$ ?

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Answer 1 · 2017-04-26T17:17:12

See the solution process below:

First, add $c$ $color(red)(c)$ to each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$a x - c + c = b + c$ $ax - c + color(red)(c) = b + color(red)(c)$

$a x - 0 = b + c$ $ax - 0 = b + c$

$a x = b + c$ $ax = b + c$

Now, divide each side of the equation by $a$ $color(red)(a)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{a x}{a} = \frac{b + c}{a}$ $(ax)/color(red)(a) = (b + c)/color(red)(a)$

$(color(red)(cancel(color(black)(a)))x)/cancel(color(red)(a)) = (b + c)/a$

$x = (b + c)/a$

Or

$x = b/a + c/a$

Answer 2 · 2017-04-26T17:17:42

$(b+c)/a$

Add 'c' in both sides, we get ax - c + c = b + c

$rArr ax = b + c$ [now divide by 'a' in both sides]

$rArr (ax)/a = (b+c)/a$

$rArr x = (b+c)/a$

How do you solve for x in ax-c=bax−c=bax-c=b?