# How do you solve for x in c=(x-a)/b?

Feb 14, 2016

$x = a + b c$

#### Explanation:

$c = \frac{x - a}{b}$

Multiply both sides by $b$.

$b c = \frac{x - a}{b} \left(b\right)$

Cancel $b$ on the right side.

$b c = \frac{x - a}{\cancel{b}} \cancel{b}$

$b c = \left(x - a\right)$

Add $a$ to both sides.

$a + b c = x$

Switch sides.

$x = a + b c$