# How do you solve for x in cx+c^2=5c^2-7cx?

Feb 23, 2016

$x = \frac{1}{2} c$

#### Explanation:

$c x + {c}^{2} = 5 {c}^{2} - 7 c x$

Dividing the L.H.S and R.HS by $c$ :

$\frac{c x + {c}^{2}}{c} = \frac{5 {c}^{2} - 7 c x}{c}$

$x + c = 5 c - 7 x$

$x + 7 x = 5 c - c$

$8 x = 4 c$

$x = \frac{4 c}{8}$

$x = \frac{1}{2} c$