Question

How do you solve for x in `dx-5c=3c`?

Answer 1

`x = "8c"/d`

Explanation:

Rearrange the equation to solve for `x`:

`dx - 5c = 3c`

`dx cancel"- 5c" cancelcolor(red)"+ 5c" = 3c + color(red)"5c"`

`dx = 8c`

`(cancel(d)x)/canceld = "8c"/d`

`x = "8c"/d`