# How do you solve for x in L = Ax + (1 + B)x?

Jun 1, 2016

$\textcolor{b l u e}{x} = \frac{L}{A + 1 + B}$

#### Explanation:

L =Acolor(blue)(x)+(1+B)color(blue)(x

L =Ax+ color(blue)(x) + Bcolor(blue)(x

$x$ is common to all three terms of the R.H.S. so we take it out as a common term.

$L = \textcolor{b l u e}{x} \left(A + 1 + B\right)$

$\textcolor{b l u e}{x} = \frac{L}{A + 1 + B}$