# How do you solve for x in n= (x+y-1)/(xy)?

Mar 9, 2016

$x = \frac{y - 1}{n y - 1}$

#### Explanation:

n = (x+y-1)/color(blue)((xy)

$n \cdot \textcolor{b l u e}{x y} = \left(x + y - 1\right)$

$n x y = x + y - 1$

Isolating terms containing $x$ towards the L.H.S:

$n x y - x = y - 1$

$x \left(n y - 1\right) = y - 1$

$x = \frac{y - 1}{n y - 1}$