How do you solve for x in #n= (x+y-1)/(xy)#?

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Answer 1 · 2016-03-09T14:07:04

#x= (y-1)/(n y -1)#

#n = (x+y-1)/color(blue)((xy)#

#n * color(blue)(xy)= (x+y-1)#

#n xy= x+y-1#

Isolating terms containing #x# towards the L.H.S:

#n xy - x= y-1#

#x(n y -1)= y-1#

#x= (y-1)/(n y -1)#