# How do you solve for y 5x+6y-12=0?

Mar 17, 2018

$y = - \frac{5}{6} x + 2$

#### Explanation:

$5 x + 6 y - 12 = 0$

To isolate $y$, we begin by transferring terms that do not contain $y$ to the opposite side of the equation.

First, let's subtract $5 x$ from both sides:

$5 x \textcolor{\mathmr{and} a n \ge}{- 5 x} + 6 y - 12 = 0 \textcolor{\mathmr{and} a n \ge}{- 5 x}$

$\implies 6 y - 12 = - 5 x$

Now let's add $12$ to both sides:

$6 y - 12 \textcolor{\mathmr{and} a n \ge}{+ 12} = - 5 x \textcolor{\mathmr{and} a n \ge}{+ 12}$

$\implies 6 y = - 5 x + 12$

Now that all the $y$ terms and non $y$ terms are on opposite sides, we can solve for $y$.

We just need to divide by $6$ on both sides:

$6 y \textcolor{\mathmr{and} a n \ge}{\div 6} = - 5 x \textcolor{\mathmr{and} a n \ge}{\div 6} + 12 \textcolor{\mathmr{and} a n \ge}{\div 6}$

$\implies \textcolor{b l u e}{y = - \frac{5}{6} x + 2}$