How do you solve for y in #2y+8x=4#?

1 Answer
May 27, 2017

Answer:

You can't; as the equation involves two variables, it takes another dissimilar equation to provide an intersection point

Explanation:

The most you can do with the equation is expressing #x# in terms of #y#:
#2y+8x=4#
#2y=-8x+4#
#y=-4x+2#
However, this only provides the Cartesian equation for a line; simply put, as it is a line, there are infinite values for x, which would correspond to infinite values for y that would satisfy the equation.