# How do you solve for y in 3x+2y= 12?

##### 1 Answer
Apr 7, 2015

The answer is $y = - \frac{3}{2} x + 6$.

$3 x + 2 y = 12$

Subtract 3x from both sides.

$2 y = 12 - 3 x$

Divide both sides by 2.

$\frac{\cancel{2} y}{\cancel{2}} = \frac{12}{2} - \frac{3}{2} x$ =

$y = 6 - \frac{3}{2} x$

$y = - \frac{3}{2} x + 6$

If this is meant to be the equation for a line in slope-intercept form, $- \frac{3}{2}$ is the slope, and $6$ is the y-intercept.