How do you solve for y in #3x+5y=7#?
# y = 1/5 (7 - 3x ) #
To find y place the other terms in the equation to the right
hand side of the equation.
Thus : 5y = 7 - 3x
( now divide both sides by 5 )
# rArr cancel(5) y/cancel(5) = (7 - 3x )/5 = 1/5 (7 - 3x ) #
Divide both sides by