How do you solve for y in #-9x - 7 = 2y + 7#?

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Answer 1 · 2018-05-28T20:54:28

#y = (-9x-14)/2# or #y = -9/2x - 7#

#-9x - 7 = 2y + 7#

To solve for #y#, we have to make #y# by itself.

First, subtract #color(blue)7# from both sides of the equation:
#-9x - 7 quadcolor(blue)(-quad7) = 2y + 7 quadcolor(blue)(-quad7)#

#-9x - 14 = 2y#

Now divide both sides by #color(blue)2#:
#(-9x - 14)/color(blue)2 = (2y)/color(blue)2#

Therefore,
#y = (-9x-14)/2#

This can also be simplified to:
#y = (-9)/2x - 14/2#

#y = -9/2x - 7#

Hope this helps!