Question

How do you solve for y in `x=(y+2)/(5y-1)`?

Answer 1

`color(blue)(y = (2 + x) / (5x - 1)`

Explanation:

`x = (color(blue)(y)+2) / (5color(blue)(y) -1)`

Our main motive in solving this question should be to isolate `color(blue)(y:`

`x * (5color(blue)(y) -1) = color(blue)(y)+2`

We multiply `x` with both terms within the bracket.

`x * (5color(blue)(y)) + x *( -1) = color(blue)(y)+2`

`5xcolor(blue)(y) -x = color(blue)(y)+2`

`5xcolor(blue)(y) - color(blue)(y) = 2 + x`

`color(blue)(y)(5x - 1) = 2 + x`

`color(blue)(y = (2 + x) / (5x - 1)`