# How do you solve for z in #4z=2z+bd#?

##### 1 Answer

Mar 6, 2016

#### Answer:

#### Explanation:

Subtract

#4z-2z=2z+bd-2z#

#2z=bd#

Divide both sides by

#z=(bd)/2#

Mar 6, 2016

Subtract

#4z-2z=2z+bd-2z#

#2z=bd#

Divide both sides by

#z=(bd)/2#

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