How do you solve for z in #a=1/2xyz#?

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Answer 1 · 2016-03-27T06:17:29

#z=(2a)/(xy)#

This is an example of literal equation

from the given #a=1/2xyz#

multiply both sides of the equation by 2

#2*a=2*1/2xyz#

#2*a=cancel2*1/cancel2xyz#

#2*a=xyz#

Divide both sides of the equation by #(xy)#

#(2*a)/(xy)=(xyz)/(xy)#

#(2*a)/(xy)=(cancel(xy)z)/(cancel(xy))#

#(2*a)/(xy)=z#

#z=(2*a)/(xy)#

God bless...I hope the explanation is useful.