Question

How do you solve for z in `a/3-z = b/3+z`?

Answer 1

`color(blue)(z) = (a- b)/(6)`

Explanation:

`a/ 3 - color(blue)(z) = b/3 + color(blue)(z`

`a/ 3 - b/3 = color(blue)(z +z`

`(a- b)/3 = color(blue)(2z`

`color(blue)(z) = (a- b)/(3 * 2)`

`color(blue)(z) = (a- b)/(6)`