How do you solve $\frac{1}{9} = 9^{4 x}$ $\frac { 1} { 9} = 9^ { 4x }$ ?

Question

1142 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-06T15:20:36

$x = - \frac{1}{4}$ $x=-1/4$

$\frac{1}{9} = 9^{4 x}$ $1/9=9^(4x)$

But $\frac{1}{9} = 9^{- 1}$ $1/9=9^-1$

So

$9^{- 1} = 9^{4 x} \Rightarrow - 1 = 4 x \Rightarrow x = - \frac{1}{4}$ $9^-1=9^(4x)rArr-1=4xrArrx=-1/4$

How do you solve 19=94x\frac { 1} { 9} = 9^ { 4x }?