# How do you solve \frac { 3b - 1} { 2} \leq 7?

Mar 25, 2018

$b \le 5$

#### Explanation:

Solve:

$\frac{3 b - 1}{2} \le 7$

Multiply both sides by $2$.

${\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}}}^{1} \times \frac{3 b - 1}{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}}} ^ 1 \le 7 \times 2$

Simplify.

$3 b - 1 \le 14$

Add $1$ to both sides.

$3 b - 1 + 1 \le 14 + 1$

Simplify.

$3 b - 0 \le 15$

$3 b \le 15$

Divide both sides by $3$.

$\frac{{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}}^{1} b}{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}} ^ 1 \le {\textcolor{red}{\cancel{\textcolor{b l a c k}{15}}}}^{5} / {\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}}^{1}$

Simplify.

$b \le 5$