Question

How do you solve `\frac { 3b - 1} { 2} \leq 7`?

Answer 1

`b<=5`

Explanation:

Solve:

`(3b-1)/2<=7`

Multiply both sides by `2`.

`color(red)cancel(color(black)(2))^1xx(3b-1)/color(red)cancel(color(black)(2))^1<=7xx2`

Simplify.

`3b-1<=14`

Add `1` to both sides.

`3b-1+1<=14+1`

Simplify.

`3b-0<=15`

`3b<=15`

Divide both sides by `3`.

`(color(red)cancel(color(black)(3))^1b)/color(red)cancel(color(black)(3))^1<=color(red)cancel(color(black)(15))^5/color(red)cancel(color(black)(3))^1`

Simplify.

`b<=5`