How do you solve #\frac { 3b - 1} { 2} \leq 7#?

1 Answer
Mar 25, 2018

Answer:

#b<=5#

Explanation:

Solve:

#(3b-1)/2<=7#

Multiply both sides by #2#.

#color(red)cancel(color(black)(2))^1xx(3b-1)/color(red)cancel(color(black)(2))^1<=7xx2#

Simplify.

#3b-1<=14#

Add #1# to both sides.

#3b-1+1<=14+1#

Simplify.

#3b-0<=15#

#3b<=15#

Divide both sides by #3#.

#(color(red)cancel(color(black)(3))^1b)/color(red)cancel(color(black)(3))^1<=color(red)cancel(color(black)(15))^5/color(red)cancel(color(black)(3))^1#

Simplify.

#b<=5#